Hi I have a question regarding the charge Q that would build up on capacitors in series when there is a potential difference between the plates.(adsbygoogle = window.adsbygoogle || []).push({});

Consider the attached circuit.

1. Knowing the potentials [tex]\phi_A, \phi_B[/tex] and the capacitances [tex]C_A, C_B[/tex], butnot[tex]\phi_C[/tex] is there a way of calculating the charges on the plates?

2. Is [tex]Q_A=Q_{Ca}[/tex] and [tex]Q_B=Q_{Cb}[/tex]?

3. Is [tex]Q_{Ca}=Q_{Cb}[/tex]? If not, what would prevent charge flowing from one plate to the other?

4. The series capacitors are equivalent to a single capacitor having capacitance

[tex]C_T=(C_AC_B)/(C_A+C_B)[/tex] and hence charge [tex]Q_T=C_TV[/tex]. Is [tex]Q_A=Q_B=Q_T[/tex]?

Sorry this is so long winded, and thanks in advance.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Charge on Capacitor plate

**Physics Forums | Science Articles, Homework Help, Discussion**