In the circuit shown in the figure, the applied potential is V_ab = 18.0V . For C_1= 3.15(microFarads) , C_2 = 5.50microF , and C_3 = 6.85microF ,
Find the charge q_1 on the capacitor C_1 (and the same for q2 on c2 and q3 on c3)
Picture is attached...
For capacitors in series: V_total= V_1+V_2+V_3...
= (Q/C)_1+ (Q/C)_2+(Q/C)_3
C_total= Q/V_total 1/C_total= (1/C)_1+(1/C)_2
In parallel: Q= Q_1+Q_2+Q_3=(CV)_1+(CV)_2+(CV)_3
The Attempt at a Solution
I tried to use Q=CV and got 5.67E-5 or 56.7(w/o changing from microF)...wrong
Then, I tried using the series equation to calculate capacitance, but it didn't work.
I'm confusing myself on how to calculate the stupid charge...