(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

I got question 10 and need help on 11

[PLAIN]http://lulzimg.com/i23/abf9f8.jpg [Broken]

2. Relevant equations

C = Q/V

3. The attempt at a solution

At first i thought it was a simple c = q/v and solve for Q but that wasnt right. Is that because the circuit splits off in two parts and a different number of charge is passed through each end based on the capacitors there?

This makes me think, if we use C = q/v, we would use the answer from question 10 to find the total charge available. Charge must be conserved so we take a percentage C_a is in comparison to the rest.. thats wrong too

Edit: I think i got the right answer but I need to double check on reasoning.

Using the idea that charge is convserved, i read in book that charges on capacitors in series are equal. Thus, it is a percentage split between (C_a+C_b) and (C_c+C_d). So what i did was find the percentage the capactiance in series for top and bottom were relative to the total capacitance of the 4. Using C = q/v with total capacitance, i found the total charge, then multiplied by the percentage.

C1+c2 was 2.05e-6

C3+c4 was 1.367e-6

Total was 3.417e-6

Thus c1+c2 was about 60% of total.

C(total) = q/v

q = 2.955e-4

q * 0.6 = 1.77e-4 C

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Charge on capacitor

**Physics Forums | Science Articles, Homework Help, Discussion**