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- David J Griffiths
But how s it valid for some conductor like →
by the way can you put this physically , I don't know this mathThe electric charge density at every point is given by Gauss's Law (Heaviside-Lorentz units)
⃗∇⋅⃗E=ρ.
Only in the electrostatic case, yes. This does not hold in magnetostatics or electrodynamics.So does that mean -
if some charge is given to an arbitrarily shaped conductor, it will surface and regardless of everything; the field inside will be zero and the surface will be equipotential
Yes. The surface is equipotential.So does that mean -
if some charge is given to an arbitrarily shaped conductor, it will surface and regardless of everything; the field inside will be zero and the surface will be equipotential
Yes. The surface is equipotential.
That does not mean that the surface charge is uniformly distributed.
I didn't mention current, nor did I imply it.Then we should have current over the surface, as its made of conductor, does that happen in steady state ?
It won't be electrostatics then !
I didn't mention current, nor did I imply it.
The surface charge density is not one uniform value over the whole surface. It varies from location to location, but it is static.
Yes.that means it is equipotential