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- David J Griffiths
But how s it valid for some conductor like →
by the way can you put this physically , I don't know this mathThe electric charge density at every point is given by Gauss's Law (Heaviside-Lorentz units)
⃗∇⋅⃗E=ρ.
Only in the electrostatic case, yes. This does not hold in magnetostatics or electrodynamics.So does that mean -
if some charge is given to an arbitrarily shaped conductor, it will surface and regardless of everything; the field inside will be zero and the surface will be equipotential
Yes. The surface is equipotential.So does that mean -
if some charge is given to an arbitrarily shaped conductor, it will surface and regardless of everything; the field inside will be zero and the surface will be equipotential
Then we should have current over the surface, as its made of conductor, does that happen in steady state ?Yes. The surface is equipotential.
That does not mean that the surface charge is uniformly distributed.
I didn't mention current, nor did I imply it.Then we should have current over the surface, as its made of conductor, does that happen in steady state ?
It won't be electrostatics then !
that means it is equipotentialI didn't mention current, nor did I imply it.
The surface charge density is not one uniform value over the whole surface. It varies from location to location, but it is static.
Yes.that means it is equipotential