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songoku
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Homework Statement
Four uncharged metal plates of the same area are placed in vacuum and separated by equal distances. They are connected by conducting wires to two resistors, two open switches and a battery. The thickness of the plates is negligible, and their area is sufficiently large. S1 is now closed, and after sufficient time elapses, a charge with quantity Q is stored in A. Next, as S1 is kept closed, S2 is also closed. After sufficient time elapses, a charge with quantity of electricity Q' is stored in A. What is the ratio of Q'/Q?
Homework Equations
Q = C.V
C = ε0 . A / d
The Attempt at a Solution
I think the circuit acts as capacitor.
When S1 is closed and S2 is open, the circuit is like capacitor between plate A and D because potential difference only applied to the two plates by the battery. Assume the distance between two adjacent plates is d, then the distance of AD = 3d. So the charge stored on A = ε0 . A / 3d . V
When both switches closed, I don't have idea how the circuit works...