Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Charge raising weak current

  1. Apr 23, 2008 #1
    I am baffled by what exactly it means to have the following (ingoing, outgoing) lepton pair configuration: [tex](0,\nu_L e_R^+)[/tex] and [tex](e_L^- \bar{\nu}_R,0)[/tex]

    This specific question was asked in Halzen and Martin exercise 12.3.

    How is it possible to have 0 in going particles and a neutrino and electron going out? I know that an ingoing right-handed antineutrino is the same as a out going lefthanded neutrino, etc, but just trying to grasp what exactly this [tex](0,\nu_L e_R^+)[/tex] and [tex](e_L^- \bar{\nu}_R,0)[/tex] configuration means physically is confusing.

    Did Halzen and Martin specifically give this example just to show one can switching ingoing and outgoing particles without looking at its physical consequences?
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you help with the solution or looking for help too?
Draft saved Draft deleted

Similar Discussions: Charge raising weak current