# Charged Bees

## Homework Statement

Measurements show that a honeybee in active flight can acquire an electrostatic charge on the order of 90.9 pC.
a)How many electrons much be transferred to produce this charge?
Ne =5.67*10^8

b) Supposing two bees, both with this charge, are separated by a distance of 14 cm. What is the magnitude of the electrostatic force between the these two bees? (You may treat the bees as point charges.)
FE= 4.0*10^-7 NO

## Homework Equations

FE=k (q1) x (q2)/r2

k=8.99 x 10^9

90.9 pC = 9.09 * 10^-11 C

14 cm = .14 m

## The Attempt at a Solution

I got part a but I cant get part b

I used Couloumb's equation and....

FE = k (9.09*10^-11)^2 / (.14)^2

and I got 4*10^-9 but it doesnt work where am i going wrong on this problem. Any help would be much appreciated. Thanks in advance.

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gneill
Mentor
In what way does 4*10^-9 "not work"?

In what way does 4*10^-9 "not work"?

I really dont know none of the answers I used worked out.

Do you know the correct answer?

ehild
Homework Helper
Calculate the force with three significant digits.

ehild

Calculate the force with three significant digits.

ehild
Thanks, it finally worked. I ended up having to use a graphing calc. to get to the significant digits. My scientific calc. was rounding, which is where my problem emerged. Thanks to everyone for the advice.