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Charged particle interaction

  • Thread starter Sashikala
  • Start date
  • #1
1
0

Homework Statement


What is the force of attraction between a uranium nucleus(atomic number 92)
and an electron at a distance of 0.1 nm?


Homework Equations



F = kQ1Q2/r2

The Attempt at a Solution



F= 8.99*109*92*1.6*10-19*(-1.6*10-19)/0.1*10-9

Please let me know the attempt at a solution is correct.
 

Answers and Replies

  • #2
69
0
well, using Coulomb's Force(like you did), you get the equation

[tex]F=\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{Q_{U}Q_{e^{-}}}{r^{2}}[/tex]

Which then, by substitution:

[tex]F=\frac{1}{4 \pi \times 8.85 \times 10^{-12}} \cdot \frac{(92 \times 1.6 \times 10^{-19}) \cdot (-1.6 \times 10^{-19})}{(0.1 \times 10^{-9})^{2}}[/tex]
 
  • #3
45
0
Yeah, it looks like you just forgot to square the radial distance.
 

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