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Charged particle interaction

  1. Apr 6, 2010 #1
    1. The problem statement, all variables and given/known data
    What is the force of attraction between a uranium nucleus(atomic number 92)
    and an electron at a distance of 0.1 nm?

    2. Relevant equations

    F = kQ1Q2/r2

    3. The attempt at a solution

    F= 8.99*109*92*1.6*10-19*(-1.6*10-19)/0.1*10-9

    Please let me know the attempt at a solution is correct.
  2. jcsd
  3. Apr 6, 2010 #2
    well, using Coulomb's Force(like you did), you get the equation

    [tex]F=\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{Q_{U}Q_{e^{-}}}{r^{2}}[/tex]

    Which then, by substitution:

    [tex]F=\frac{1}{4 \pi \times 8.85 \times 10^{-12}} \cdot \frac{(92 \times 1.6 \times 10^{-19}) \cdot (-1.6 \times 10^{-19})}{(0.1 \times 10^{-9})^{2}}[/tex]
  4. Apr 6, 2010 #3
    Yeah, it looks like you just forgot to square the radial distance.
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