(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Identical isolated conducting spheres 1 and 2 have equal charges q and are

separated by a distance r large compared to the diameters of the spheres. The electrostatic

force acting on sphere 2 due to sphere 1 is 3.10-6N. Suppose now, that the third identical sphere 3, having an isolating handle, and initially electrically neutral, is touched first to the sphere 1, then to the sphere 2, and finally removed. Find the electrostatic force which will be acting on the sphere 2 after all these manipulations.

2. Relevant equations

Coulombs Law: Fe= Ke ((q1)(q2)/r^2)

Gausses Law:E*A

3. The attempt at a solution

Wel, we know that q1=q2. That means that both particles are going to move away from each other. I have that q2 has Fe= 3*10^6. The part I don't understand what does Sphere 3 do to my Sphere 2? I know that distance between q1 and q2 is r= ((Keq1q2)/F2)^1/2. I am simply stuck on the part of Sphere 3. Anyone want to shed some light?

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# Homework Help: Charged Particles Probem

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