Calculating Electric Field for Charged Ring on x,y Axes

In summary, the conversation discusses finding the potential and electric field for a charged ring with a charge density of -lambda on the top half and +lambda on the bottom half, located at the center of the x,y axes. The equation for the electric field is given as E=(lay^)/(2pi epsR), and the individual is having trouble finding the potential for this equation. Suggestions are given, and a discrepancy is noted in the equation.
  • #1
mickry
6
0

Homework Statement



I have the field at the center of a charged ring on the x,y axes (top half has charge density of -lambda, bottom is +lambda lambda=la) to be
E=(lay^)/(2pi epsR) (eps=epsilon) i can't find the potential for this, R=radius,
Can anyone help?

Homework Equations





The Attempt at a Solution

 
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  • #2
Normally, it's easier to find the potential first, as it is a scalar, and then take the partial derivative with respect to the distance variable to determine the E-Field.

In this case, your expression doesn't make sense.

[tex]
E = \frac{\lambda y}{2 \pi \epsilon_0 R}
[/tex]

Are you sure that's correct? Because that implies that as you get further away from the ring, the e-field increases, which doesn't make sense.
 

1. How do you calculate the electric field for a charged ring on the x,y axes?

To calculate the electric field for a charged ring on the x,y axes, you can use the equation E = kQx/(x^2 + y^2)^(3/2), where k is the Coulomb's constant, Q is the charge of the ring, and x and y are the coordinates on the x,y axes.

2. What is the direction of the electric field for a charged ring on the x,y axes?

The direction of the electric field for a charged ring on the x,y axes will depend on the location of the point in relation to the ring. If the point is on the axis of the ring, the electric field will be perpendicular to the axis. If the point is above or below the axis, the electric field will be directed away from or towards the ring, respectively.

3. Can you calculate the electric field at a point inside the ring's radius?

No, this equation for calculating the electric field is only valid for points outside the ring's radius. Inside the ring, the electric field would be zero due to cancellation of the contributions from different parts of the ring.

4. How does the electric field change as the distance from the ring increases?

As the distance from the ring increases, the magnitude of the electric field decreases. This can be seen in the denominator of the equation, where the distance (x^2 + y^2) is squared and raised to the power of 3/2. This means that the electric field will decrease at a faster rate as the distance increases.

5. Can you use this equation to calculate the electric field for a charged ring on the z-axis?

No, this equation is only valid for points on the x,y axes. To calculate the electric field for a charged ring on the z-axis, a different equation would need to be used.

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