# Charged ring.

1. Feb 23, 2007

### mickry

1. The problem statement, all variables and given/known data

I have the field at the center of a charged ring on the x,y axes (top half has charge density of -lambda, bottom is +lambda lambda=la) to be
E=(lay^)/(2pi epsR) (eps=epsilon) i cant find the potential for this, R=radius,
Can anyone help?

2. Relevant equations

3. The attempt at a solution

2. Feb 23, 2007

### Saketh

Normally, it's easier to find the potential first, as it is a scalar, and then take the partial derivative with respect to the distance variable to determine the E-Field.

In this case, your expression doesn't make sense.

$$E = \frac{\lambda y}{2 \pi \epsilon_0 R}$$

Are you sure that's correct? Because that implies that as you get further away from the ring, the e-field increases, which doesn't make sense.