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Homework Help: Charged ring.

  1. Feb 23, 2007 #1
    1. The problem statement, all variables and given/known data

    I have the field at the center of a charged ring on the x,y axes (top half has charge density of -lambda, bottom is +lambda lambda=la) to be
    E=(lay^)/(2pi epsR) (eps=epsilon) i cant find the potential for this, R=radius,
    Can anyone help?

    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Feb 23, 2007 #2
    Normally, it's easier to find the potential first, as it is a scalar, and then take the partial derivative with respect to the distance variable to determine the E-Field.

    In this case, your expression doesn't make sense.

    E = \frac{\lambda y}{2 \pi \epsilon_0 R}

    Are you sure that's correct? Because that implies that as you get further away from the ring, the e-field increases, which doesn't make sense.
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