Charged ring.

  • Thread starter mickry
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  • #1
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Homework Statement



I have the field at the center of a charged ring on the x,y axes (top half has charge density of -lambda, bottom is +lambda lambda=la) to be
E=(lay^)/(2pi epsR) (eps=epsilon) i cant find the potential for this, R=radius,
Can anyone help?

Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
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Normally, it's easier to find the potential first, as it is a scalar, and then take the partial derivative with respect to the distance variable to determine the E-Field.

In this case, your expression doesn't make sense.

[tex]
E = \frac{\lambda y}{2 \pi \epsilon_0 R}
[/tex]

Are you sure that's correct? Because that implies that as you get further away from the ring, the e-field increases, which doesn't make sense.
 

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