Finding the Maximum Electric Field of a Charged Ring

In summary, we are considering a charged ring with a radius of 20.6 cm and a total charge of 12 nC. We want to find the maximum electric field at a perpendicular distance z away from the center of the ring. The equation for the electric field of a ring of charge is given as Ering = (1/4 pi eo) (zQ/(z^2+R^2)^(3/2)). To find the maximum field, we need to differentiate the function E(x) = [k*Q /(x^2 + r^2)]*[x/sqrt(x^2+r^2)] and find where dE/dx = 0. It is important to note that in this
  • #1
05holtel
52
0

Homework Statement




Consider a charged ring of radius 20.6 cm and total charge 12 nC.

We are interested in the electric field a perpendicular distance z away from the center of the ring.

At what distance from the center of the ring does the electric field become maximum?

Hint: The field for a ring of charge is:

Ering = (1/4 pi eo) (zQ/(z^2+R^2)^(3/2))

Homework Equations




The Attempt at a Solution



When x = 0, the fields due to segments of the ring cancel out. As x -> infinity, the field falls with 1/x^2 behavior, so there has to be a maximum E for some x.

When adding up the fields due to each arc segment, you only have to add the x-components (along the axis) because the others will cancel out.

Here is what I get for E as a function of x:

E (x) = [k*Q /(x^2 + r^2)]*[x/sqrt(x^2+r^2)]
The second term in brackets is the cosine of the angle that defines the component in the x direction.

That function must be differentiated to find where the field is a maximum.


1) is this right so far
2) if so how do I differentiate this
 
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  • #2
05holtel said:

Homework Statement




Consider a charged ring of radius 20.6 cm and total charge 12 nC.

We are interested in the electric field a perpendicular distance z away from the center of the ring.

At what distance from the center of the ring does the electric field become maximum?

Hint: The field for a ring of charge is:

Ering = (1/4 pi eo) (zQ/(z^2+R^2)^(3/2))

Homework Equations




The Attempt at a Solution



When x = 0, the fields due to segments of the ring cancel out. As x -> infinity, the field falls with 1/x^2 behavior, so there has to be a maximum E for some x.

When adding up the fields due to each arc segment, you only have to add the x-components (along the axis) because the others will cancel out.

Here is what I get for E as a function of x:

E (x) = [k*Q /(x^2 + r^2)]*[x/sqrt(x^2+r^2)]
The second term in brackets is the cosine of the angle that defines the component in the x direction.

That function must be differentiated to find where the field is a maximum.


1) is this right so far
2) if so how do I differentiate this

Well if the field starts off at zero at x= 0 then increases, and then dies off again, then I think we would look at where dE/dx = 0 as this is where the slope of an E v. x graph would be maximum.

In the equation given, they give you the e-field function of this ring, with Z being your X? Or is Z supposed to be the radius of the ring, or is R the radius of the ring and not the distance from a specific segment of the ring of charge to the point of interest?
 
  • #3
In others words, r is usually the distance from some charge to some place you are looking for the E field. In the equation you were given, is r the radius of the charged ring, or the distance from the charge to the place of interest..?
 

1. What is a charged ring?

A charged ring is a circular object that has an electric charge distributed evenly along its circumference. This charge creates an electric field around the ring.

2. How do you find the maximum electric field of a charged ring?

To find the maximum electric field of a charged ring, you can use the equation E = kQ/r², where E is the electric field strength, k is the Coulomb's constant, Q is the charge of the ring, and r is the distance from the center of the ring to the point where you want to find the electric field.

3. What factors affect the maximum electric field of a charged ring?

The maximum electric field of a charged ring is affected by the charge of the ring, the distance from the center of the ring to the point where you want to find the electric field, and the value of the Coulomb's constant.

4. How is the maximum electric field of a charged ring different from the electric field of a point charge?

The maximum electric field of a charged ring is different from the electric field of a point charge because a charged ring has a non-zero radius and the charge is distributed along its circumference, while a point charge has a single point of concentration of charge.

5. What are some real-life applications of finding the maximum electric field of a charged ring?

The maximum electric field of a charged ring is used in various real-life applications, such as in the design of electric motors and generators, in the study of electric fields in space, and in the manipulation of charged particles in particle accelerators.

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