# Charged Rod

1. Feb 7, 2006

### hoseA

http://img209.imageshack.us/img209/2646/chargedrod1ew.png [Broken]

I used the equation:

kq/(d(d+L))

I converted everything to meters before doing the calculations. (I'm kind of pressed for time at the moment... i'll post the actual work in 2 hours.)

I want to make sure the equation is right.

Last edited by a moderator: May 2, 2017
2. Feb 7, 2006

### Gokul43201

Staff Emeritus
1. An equation must contain an equality. What you've written is an expression. What is it an expression for ? And what do the variables represent ?

2. Have you learnt integration ? If you have, I suspect you are required to derive the equation (it's just a 4-line derivation) for the field and substitute the values.

3. Assuming d is the distance to the center of the rod, that is not the equation I get for the field.

3. Feb 7, 2006

### hoseA

any more hints? i have to submit my hw in 20 min.

4. Feb 7, 2006

### hoseA

Nevermind. i got it. Thanks for the help Gokul.

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