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Charged Sphere

  1. Jan 12, 2010 #1
    1. The problem statement, all variables and given/known data

    I'm supposed to find the net force that the southern hemisphere of a uniformly charged sphere exerts on the northern hemisphere. I must express my answer in terms of the radius [tex]R[/tex] and the total charge [tex]Q[/tex].



    2. Relevant equations

    [tex]F = QE[/tex]

    [tex]\int E[/tex] [tex] da = \frac{1}{\epsilon_{0}}Q[/tex]



    3. The attempt at a solution

    From the second equation, I can get an expression for [tex]E[/tex] which gives me the area and multiply the whole expression by [tex]Q[/tex] to get the net force. But I am not getting the right answer. I'm guessing the area I have is incorrect. Unless the whole procedure is incorrect from the beginning.
     
  2. jcsd
  3. Jan 12, 2010 #2

    gabbagabbahey

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    Homework Helper
    Gold Member

    Is the electric field constant (both in magnitude and direction) over the entire hemispherical volume? If not, you cannot simply multiply "the" field by the total charge of the hemisphere to get the net force on the surface. A small piece of charge in one part of the hemisphere will experience a different force than a small piece in a different part of the hemisphere.

    Instead, treat each infinitesimal piece [itex]dV[/itex] at position [itex]\textbf{r}[/itex] (relative to the center of the sphere)of the northern hemisphere as a point charge with charge [itex]dq=\rho dV[/itex]...it will experience a force [itex]d\textbf{F}=\textbf{E}(\textbf{r})dq=\rho\textbf{E}(\textbf{r})dV[/itex]...Integrate over the hemisphere (add up these small forces) to get the net force on the hemisphere.

    Also, consider carefully whether to use the field due to just the southern hemisphere, or the field due to the entire sphere in your calculations....does it matter? Why or why not?:wink:
     
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