Charges and Trig question

  • #1
Lilian Chan
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Homework Statement


link: https://ibb.co/Xy9s6DR
What is the magnitude of this force?

Homework Equations


Coulomb's Law
Trig equations

The Attempt at a Solution


(.05 m)xcos(60)=0.025m (the distance between the two known charges)
F(between the two known charges)=(9x20^9)(1x10^-9)(10x10^-9)/(0.025)^2=1.44x10^-4
F(that points down)=sin(60)*1.44x10^-4=1.25x10^-4N

The homework system says I got it wrong but I'm not seeing where.
 

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Answers and Replies

  • #2
haruspex
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(9x20^9)
9x10^9
F(between the two known charges)
That's only the force between those two charges. The F in the diagram is the net force on the -1nC charge from the other two.
 

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