Charging by contact

  • Thread starter slickvic
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  • #1
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Suppose you let identical pith balls come in contact to make q1=q2. Would the charges be equal if the pith balls were of different size?
 

Answers and Replies

  • #2
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You know, I vaguely remember doing this problem way back in freshman physics. Just a guess on my part, but I think that putting the balls in contact would make the charge density uniform. If my assumption is correct, then when you separate the balls, the smaller one would contain less charge.
 
  • #3
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I'm not real sure about pith, but I can answer for metal balls...

Putting the balls in contact forces their potential to be the same. The problem is easier if the balls are separated by a distance large compared to their size. Briefly connecting them with a wire would force the potential at each ball to be the same. In this case the ratio of charges would be equal to the ratio of the radii.
 
  • #4
905
4
I'm not real sure about pith, but I can answer for metal balls...

Putting the balls in contact forces their potential to be the same. The problem is easier if the balls are separated by a distance large compared to their size. Briefly connecting them with a wire would force the potential at each ball to be the same. In this case the ratio of charges would be equal to the ratio of the radii.

Are you sure it wouldn't be equal to the ratio of the cube of their radii?

I'm asking because I'm also considering lesser dimensional problems. What if, instead of spheres, we were talking about disks, or straight rods? Well, maybe I should work the problem for myself and get back to you guys.
 

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