A 2600-nF capacitor is disconnected from the 15-V battery and used to charge three uncharged capacitors, a 100-nF capacitor, a 200-nF capacitor, and a 300-nF capacitor, connected in series.
After charging, what is the potential difference across each of the four capacitors?
Qo = CV = 3.9e-5 C
Qo = Q234C1[(1/100)+(1/200)+(1/300)] + Q234
The Attempt at a Solution
Qo = 5.33Q234
Qo = 3.9e-5 C
Q234 = 7.32e-6 C
Q1/C1 = (Qo-Q234)/C1 = [(3.9e-5 C) - (7.32e-6 C)]/2600 nF = 12.2 V
V2 = (7.32e-6 C)/100 nF = 7.32 V
V3 = (7.32e-6 C)/200 nF = 3.65 V
V4 = (7.32e-6 C)/300 nF = 2.43 V
This is incorrect, and I haven't been able to figure out what's wrong.