1. The problem statement, all variables and given/known data A 2600-nF capacitor is disconnected from the 15-V battery and used to charge three uncharged capacitors, a 100-nF capacitor, a 200-nF capacitor, and a 300-nF capacitor, connected in series. After charging, what is the potential difference across each of the four capacitors? 2. Relevant equations Qo = CV = 3.9e-5 C Qo = Q234C1[(1/100)+(1/200)+(1/300)] + Q234 3. The attempt at a solution Qo = 5.33Q234 Qo = 3.9e-5 C Q234 = 7.32e-6 C Q1/C1 = (Qo-Q234)/C1 = [(3.9e-5 C) - (7.32e-6 C)]/2600 nF = 12.2 V V2 = (7.32e-6 C)/100 nF = 7.32 V V3 = (7.32e-6 C)/200 nF = 3.65 V V4 = (7.32e-6 C)/300 nF = 2.43 V This is incorrect, and I haven't been able to figure out what's wrong.