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jpas

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This is supost to be a classic. I solved it but my answer isn´t right and I can´t find out why. Hope you guys can help.

Imagine an equilateral triangle with one turtle on each side of lenth L. All turtles move with velocity

The movement will be something like this.

Relative to turtle 2, turtle 1 will be in uniform rectilinear motion and its velocity will be:

[tex] \vec V_{12}=\vec v_1 - \vec v_2 [/tex]

[tex]\vec v_1[/tex] and [tex]\vec -v_2 [/tex] make an angle of 60º degrees. So,

[tex] V_{12}= \frac{V}{\sqrt{3}} [/tex]

Relative to turtle 2, turtle 1 will only travel the distance that separates it from the center of the triangle, which is [tex] \frac{L}{3}[/tex]

So, [tex] t= \frac{v_{12}}{d} = \frac{L}{3V} [/tex]

P.S.: I guess some of you might have already solved this problem. If not, I recommend it, though I got it wrong.

Imagine an equilateral triangle with one turtle on each side of lenth L. All turtles move with velocity

**V**. Turtle 1 always directs its motion to turtle 2, turtle 2 to turtle 3, and turtle 3 to turtle 1, again. Calculate the time the turtles take to meet.The movement will be something like this.

Relative to turtle 2, turtle 1 will be in uniform rectilinear motion and its velocity will be:

[tex] \vec V_{12}=\vec v_1 - \vec v_2 [/tex]

[tex]\vec v_1[/tex] and [tex]\vec -v_2 [/tex] make an angle of 60º degrees. So,

[tex] V_{12}= \frac{V}{\sqrt{3}} [/tex]

Relative to turtle 2, turtle 1 will only travel the distance that separates it from the center of the triangle, which is [tex] \frac{L}{3}[/tex]

So, [tex] t= \frac{v_{12}}{d} = \frac{L}{3V} [/tex]

P.S.: I guess some of you might have already solved this problem. If not, I recommend it, though I got it wrong.

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