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Chebyshev's Inequality (Statistics Question)

  1. Apr 28, 2005 #1
    Could someone tell me how to find the k in Chebyshev's inequality??
     
  2. jcsd
  3. Apr 28, 2005 #2

    xanthym

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    Parameter "k" is the number of standard deviations "σ" on either side of the mean "μ" for which a lower bound of the included distribution {fraction between (μ-kσ) and (μ+kσ)} is required {and given by this inequality to be (1 - 1/k2)}. See also Msg #4 at the following site (Form #1 in this Msg is most commonly used):

    https://www.physicsforums.com/showthread.php?t=70789


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    Last edited: Apr 28, 2005
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