Hi. I'm having a bit of trouble with Chebyshev's inequality and I was wondering if someone could point me in the right direction as to how to answer this question: Use chebyshev's theorem to verify that the probability is at least 35/36 that in 900 flips of a balanced coin the proportion of heads will be between 0.40 and 0.60. By the looks of it, I have to use E(Y)=p, variance(Y)=p(1-p)/n. I'm not quite sure how to approach this as my lecturer didn't cover this in much depth. Thank you.