Check another trig behaviour

  • Thread starter aisha
  • Start date
  • #1
aisha
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[tex] y=2\cos (\frac {-1} {2}x + 90 ) -3 [/tex]

I changed the original function to

[tex] y=2\cos [\frac {-1} {2} (x-180)] -3 [/tex]

period=-4pi
amplitude=2
max=-1
min=-5
range={y:-5<=y<=-1}
domain={x:XER}
vertical displacement 3 units down
horizontal translation 180 units left
 
Last edited:

Answers and Replies

  • #2
HallsofIvy
Science Advisor
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We can't tell- there is no "x" in the original function.
 
  • #3
iNCREDiBLE
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aisha: do not confuse radians and degrees.
 
  • #4
aisha
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I don't think I am confused about radians and degrees some of my trig functions have radians in them so to make things simpler I convert to degrees but in this question i haven't done any converting that 90 is in degrees. :smile:
sorry I added the x in the original function.
 
  • #5
aisha
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Did i do this question correctly?
 
  • #6
TD
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Yes, seems correct although I think the horizontal displacement is to the right.
 
  • #7
LeonhardEuler
Gold Member
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If the original question had 90 in it, then you did it correctly except for the direction of the horizontal translation. If the original question had [itex]\frac{\pi}{2}[/itex] in it, then the value of the horizontal translation is off too.
 
  • #8
aisha
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0
thanks so much the original question does have 90 degrees in it. You are right the horizontal translation should be to the right NOT LEFT! :smile:
 

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