- #1

- 21

- 0

n+1 0<=n<=2

x[n]=

0 otherwise

h[n]= a^n u[n]

**solution:**

y[n]= a^n + 2a ^n-1 + 3 a^n-2

y[n]= a^n + 2a ^n-1 + 3 a^n-2

is it right?

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- Thread starter angel23
- Start date

- #1

- 21

- 0

n+1 0<=n<=2

x[n]=

0 otherwise

h[n]= a^n u[n]

y[n]= a^n + 2a ^n-1 + 3 a^n-2

is it right?

- #2

vsage

Looks to be, except for the part where you seem to ignore what the step function u[n] does to the solution.

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