Check my solution.

  • Thread starter angel23
  • Start date
  • #1
21
0
find convolution of.


n+1 0<=n<=2
x[n]=

0 otherwise

h[n]= a^n u[n]

solution:
y[n]= a^n + 2a ^n-1 + 3 a^n-2


is it right?
 

Answers and Replies

  • #2
vsage
Looks to be, except for the part where you seem to ignore what the step function u[n] does to the solution.
 
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