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Homework Help: CHECK PLEASE Tan BEHAviour IN TRANSFORMATION

  1. Sep 13, 2005 #1
    HOw does [tex] y-3=-\tan (-2x+\pi) [/tex] differ from [tex] y=tan(x) [/tex]

    [tex] y=-\tan [-2 (x+ \frac {\pi} {2} )] +3 [/tex] rearranged

    It differs because it has a

    Horizontal compression by a factor of 1/2
    it is reflected in the x and y axis
    there is a horizontal translation [tex] \frac {\pi} {2} [/tex] units to the left
    and a vertical displacement 3 uinits up.

    Can someone please tell me if I made any mistakes?
     
  2. jcsd
  3. Sep 13, 2005 #2

    HallsofIvy

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    Looks like a good start.
     
  4. Sep 13, 2005 #3
    hallosivy, shouldnt that be -2(x-pi/2) instead of plus ?
     
  5. Sep 13, 2005 #4

    HallsofIvy

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    Yep, sorry, didn't look close enough.
     
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