1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: CHECK PLEASE Tan BEHAviour IN TRANSFORMATION

  1. Sep 13, 2005 #1
    HOw does [tex] y-3=-\tan (-2x+\pi) [/tex] differ from [tex] y=tan(x) [/tex]

    [tex] y=-\tan [-2 (x+ \frac {\pi} {2} )] +3 [/tex] rearranged

    It differs because it has a

    Horizontal compression by a factor of 1/2
    it is reflected in the x and y axis
    there is a horizontal translation [tex] \frac {\pi} {2} [/tex] units to the left
    and a vertical displacement 3 uinits up.

    Can someone please tell me if I made any mistakes?
     
  2. jcsd
  3. Sep 13, 2005 #2

    HallsofIvy

    User Avatar
    Science Advisor

    Looks like a good start.
     
  4. Sep 13, 2005 #3
    hallosivy, shouldnt that be -2(x-pi/2) instead of plus ?
     
  5. Sep 13, 2005 #4

    HallsofIvy

    User Avatar
    Science Advisor

    Yep, sorry, didn't look close enough.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook