Hi all I am have a problem with this question I have used two method to solve and get two different ans, could someone please point where I am going wrong 1. The problem statement, all variables and given/known data Five cards are dealt from a standard shuffled deck. What is the probability that: There is at least one card from each of the four suits? I wanted to see if I could attempt this question a different way to see if I could get the correct ans two ways. So what I did was say I pick 3 cards 2 from the same suit and one from another. What I would like to know is my intuition correct because when I applied the same logic to the question above I got the same ans, I just want to make sure that I am not just getting the right ans from wrong workings Now my ans for actual question which is in bold (13C2*13^3)/52C5 2. Relevant equations 3. The attempt at a solution So what I did was to say that if I pick 3 cards 2 of the same suit from a 52 card deck I could use combinations to calculate the probability: (13C2*13C1)/52C3 this gve me an ans of 39/850 This is the ans if I just say picked hearts twice as there are four suits I need to multiply through by 4 Now I the attempted the question like this: P(HHO)=13/52 *12/51 * 39/50= 39/850 I got a bit confused thinking to my self should I not work out P(HOH) and P(OHH) but then I re read the question half a dozen times think order dose not matter therefore I only need to calculate P(HHO) thus the ans are the same, I then applied the the same logic to the question above and got the same ans. Is this the right way about thinking about this question?