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Check the working ( set )

  • Thread starter denian
  • Start date
  • #1
160
0
using algebraic laws of sets, show that, for any set A and set B that

( A U B ) [inter] ( A U B' ) = A


this is my working

( A U B ) [inter] ( A U B' )

= A U ( B [inter] A ) U ( B [inter] B' )

= ( A U B ) [inter] ( A U A )

= ( A U B ) [inter] A

= A U ( B [inter] A )

= A ( shown )


i think this working is wrong. is there other way better than this?
 

Answers and Replies

  • #2
508
0
denian,
I think the 1st step should be

( A U B ) [inter] ( A U B' )

= A[inter]A U A[inter]B' U B[inter]A U B[inter]B'
 
  • #3
160
0
ok. i dont even know we can expand it that way.
thank you.
 

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