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Check this for me involving sin theta

  1. Feb 26, 2005 #1
    Check this for me plz involving sin theta

    For sin theta= -0.4321, 0<=theta<=2pi

    QUESTIONS

    a) How many solutions are possible?
    b)In which quadrants would you find the solutions?
    c)Determine the reference angle for this equation to the nearest degree.
    d) Determine all the solutions to the equation to the nearest degree

    MY ANSWERS

    a) 2
    b) quadrants 3 and 4
    c)-26 degrees (im not sure if the negative should be there)
    d)solutions theta=334 degrees and theta=206 degrees

    Can someone please check to see if Im on the right track please
     
  2. jcsd
  3. Feb 26, 2005 #2

    dextercioby

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    I don't know what they mean by reference angle (you may wanna consult the book),but the rest looks perfect to me...:smile: :wink:

    Daniel.
     
  4. Feb 26, 2005 #3
    Thanks does anyone know if the reference angle is correct or not if its not then the solutions should be wrong too :approve:
     
  5. Feb 26, 2005 #4

    dextercioby

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    The solutions (point "d") are correct,no doubt about it...:wink:

    Daniel.
     
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