1. The problem statement, all variables and given/known data Your home video studio will use a TV antenna cable often known as "twin lead." Two 0.50mm--diameter wires are spaced 12mm apart. Your equipment requires that the total capacitance of the cable not exceed 1000 pF. The cable is 30m long. A technical paper on the cable gives the potential difference between the two conductors as V = lamda / (pi*epsilon_0 ) * ln ( (b-a) / a ) where a is the radius of the wire and b is the separation. Is your cable within the specifications? ____ (my answer is NO), see below Attempt : C = epsilon_0 * A / D A = 2piRL A = 2 * pi * ( 0.5/2 * 10^-3 ) * (30 m) D = 12mm * 10 ^ -3 C = epsilon_0 * 2 * pi * (0.25 * 10^-3) * (30) / (12 * 10^-3) = 3.47 * 10 ^ -11 which is greater than 1000pF = 10^-9, thus it should be NO, I think. Is this correct?