- #1
ladyrae
- 32
- 0
Am I on the right track?
Use the Summation Rule to find f ' (x) and simplify where possible:
f ' (x) = [tex] \frac {\sqrt {x}} {3} - \frac {3} {\sqrt {x}} + \frac {2} {x^3} [/tex]
= [tex] \frac {1}{3} (\frac {1}{2} x^{-\frac {1}{2}}) - 3(-\frac {1}{2} x^{-\frac{3}{2}}) + 2(-3{x^{-4}}) [/tex]
= [tex] \frac {1} {6\sqrt {x}} + \frac {3} {2x^{\frac{3}{2}}} - \frac{6} {x^{4}} [/tex]
Use the Summation Rule to find f ' (x) and simplify where possible:
f ' (x) = [tex] \frac {\sqrt {x}} {3} - \frac {3} {\sqrt {x}} + \frac {2} {x^3} [/tex]
= [tex] \frac {1}{3} (\frac {1}{2} x^{-\frac {1}{2}}) - 3(-\frac {1}{2} x^{-\frac{3}{2}}) + 2(-3{x^{-4}}) [/tex]
= [tex] \frac {1} {6\sqrt {x}} + \frac {3} {2x^{\frac{3}{2}}} - \frac{6} {x^{4}} [/tex]