Solving Hard Chemistry Equations

[dagg3r]

CHEM EQUAtioNS HARD!

hi can anybody show me if i am writing these equations right or not thanks

Fe3+ + 6H20 -> F2(H20)6 3 +


Fe(H20)6 3+ + h20 -> Fe(h20)5(OH) 2+ + H30+

when added HCL

Fe(H20)5(OH) 2+ + 4Cl- -> Fe(OH)cl4 2- + 5H20

when added KSCN

Fe(OH)cl4 2- + SCN- -> Fe(Oh)SCN- + KCl4 2-

when added KF

Fe(OH)SCN- + KF -> KSCN + Fe(Oh)F-

 

[Gokul43201]

hi can anybody show me if i am writing these equations right or not thanks

We can only check if they are balanced and possible. Whether they will really happen will depend on the conditions - so without the actual question, it would be hard to tell truth from fiction.

Please post the original question.

Fe3+ + 6H20 -> F2(H20)6 3 +


Fe(H20)6 3+ + h20 -> Fe(h20)5(OH) 2+ + H30+

Close, but not really balanced.

when added HCL

Fe(H20)5(OH) 2+ + 4Cl- -> Fe(OH)cl4 2- + 5H20

when added KSCN

Fe(OH)cl4 2- + SCN- -> Fe(Oh)SCN- + KCl4 2-

This is really wrong. Recheck it.

when added KF

Fe(OH)SCN- + KF -> KSCN + Fe(Oh)F-

Mistake carried over from previous step.

 

[ravenprp]

Hi there,

It looks like you are on the right track with these equations! However, there are a few things to keep in mind when solving hard chemistry equations:

1. Make sure your chemical formulas are balanced. This means that the number of atoms of each element on the reactant side should equal the number of atoms on the product side.

2. Pay attention to the charges of the ions. In your first equation, the Fe3+ ion should have a charge of 3+ on both the reactant and product side. In the second equation, the H3O+ ion should have a charge of 1+ on both sides.

3. When adding HCl, you are correct in forming Fe(OH)Cl4 2- as a product. However, the correct formula for this compound should be Fe(OH)2Cl2.

4. When adding KSCN, you are correct in forming Fe(OH)SCN- as a product. However, the correct formula for this compound should be Fe(OH)SCN.

5. Lastly, when adding KF, you are correct in forming Fe(OH)F- as a product. However, the correct formula for this compound should be FeF2.

Remember to always double check your chemical formulas and charges to ensure that your equations are correct. Keep up the good work!