this is one of lab question but i don't even understand plz help me(adsbygoogle = window.adsbygoogle || []).push({});

the question is

1. consider spherical atoms of radius R arranged in a cube closest-packed lattice. if a small cube is constructed so that its corners are at the centers of the corner atoms, then one-eighth of each corner atom and one-half of each face-centered atom lies within the small cube. what is the total number of atoms within the small cube? calculate the volume occupied by these atoms, the volume of the cube, and the fraction of the available space that is occupied by atoms.

2. show that for spherical atoms in a body-centered cubic structure exactly 68.0 percent of the available space is occupied by atoms. (hint : begin by constructing cube like the one described in question 1

plz..if u know help me

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# Chem lab help~!

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