1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Chem Problem

  1. Sep 18, 2007 #1
    1. The problem statement, all variables and given/known data


    "De-icing salt" is used to melt snow and ice on streets. the highway department of a small town is decideing whether to by NaCl or CaCl2 for the job. The town can obtain NaCl for $0.36/kg. What is the maximum the town should pay for CaCl2 to be cost effective? in kg



    2. Relevant equations



    3. The attempt at a solution


    I am sure this is very simple but im not sure what to do with it....
     
  2. jcsd
  3. Sep 18, 2007 #2

    mgb_phys

    User Avatar
    Science Advisor
    Homework Helper

    Do you know about moles and molar mass of compounds?
    Do you know how to work out how much NaCl there is in a kg?

    You have posted 3 questions which are basically the same thing - they all need this step.
     
  4. Sep 18, 2007 #3
    I am really not sure.....i am pretty new to chemistry and not very good at it, can i get some help
     
  5. Sep 18, 2007 #4

    hage567

    User Avatar
    Homework Helper

    Can you work out how many moles are in 1 kg of NaCl and CaCl2? What part are you confused on?
     
  6. Sep 18, 2007 #5
    i worked out .05844 mol in 1 kg for NaCL
    and .11098 mol in 1 kg of CaCl2

    is this correct
     
  7. Sep 19, 2007 #6

    mgb_phys

    User Avatar
    Science Advisor
    Homework Helper

    No, molar mass of NaCl is 58.4g, CaCl2 is 111g
    but for every mole of CaCl2 you get twice as much Cl as you do from NaCl

    So 1kg of NaCl gets you 17.12moles of Na and Cl, 1kg of CaCl2 is 9.0 moles of Ca and 18.0moles of Cl

    It isn't clear from the question if you supposed to take into account the de-icing effect of the Cl ion so the answer is either.
    That you should pay 9/17.2 = 0.52 times as much for CaCl2
    or if you are only concerned about Cl then you should pay 18/17.2 = 1.05 times as much for CaCl2


    (Actually it's a very stupid example because CaCl2 is so hydroscopic it will almost certainly not be 111g/mole - but since this is an intro chemistry question you can ignore this)
     
    Last edited: Sep 19, 2007
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Chem Problem
  1. Chem problem (Replies: 3)

  2. Chem Problem (Replies: 8)

  3. Chem problem (Replies: 1)

Loading...