Calculating Molar Volume of H2 Gas at STP with Mg Ribbon | Chemistry Question

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In summary, to find the molar volume of a gas, specifically H_{2}, one can use a Mg ribbon to react with the gas and measure its volume in a test tube. Using the formula V_{1} = \frac{P_{1}}{T_{1}} \times \frac{T_{2}}{P_{2}}, with experimental values, the calculated volume was 1.234. To find the molar volume, the moles of H_{2} gas are divided by the volume of the gas. It is possible to have a small amount of moles, such as 0.0025, if only a small amount of gas reacted, such as with a 1.20 gram Mg strip
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courtrigrad
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Lets say you want to find the molar volume of a gas ([tex] H_{2} [/tex] specifically). So you basically use a [tex] Mg [/tex] ribbon and find the volume of the [tex] H_{2} [/tex] gas in a test tube with the [tex] Mg [/tex] ribbon. The water fizzes and bubbles. I am having trouble finding the volume of [tex] H_{2} [/tex] at STP. I used the formula: [tex] V_{1} = \frac{P_{1}}{T_{1}} \times \frac{T_{2}}{P_{2}} [/tex]. After plugging in experimental values I got 1.234. Does this make sense? What units is this in. To find the molar volume I know that I do the moles of H_2 gas divided by the volume of H_2 gas. Does it make sense to only have 0.0025 moles of H_{2} gas reacted? Because I se a Mg strip that was 1.20 grams.

Any help is appreciated

Thanks
 
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Is that the combined gas equation?

[tex]\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}} [/tex]

Molar volume is the gas' volume divided by the moles of gas.
 
  • #3
for sharing your question and experiment! It sounds like you are on the right track in using the ideal gas law (PV = nRT) to calculate the molar volume of H2 gas at STP. The formula you used, V1 = (P1/T1) x (T2/P2), is a rearranged version of the ideal gas law where V1 represents the initial volume of the gas, P1 and T1 represent the initial pressure and temperature, and P2 and T2 represent the final pressure and temperature.

The units for V1 in your calculation would depend on the units used for pressure and temperature. If you used standard units of pressure (atm) and temperature (K), then the volume would be in liters (L).

It is possible to have a small amount of moles of gas reacted, as in your case with 0.0025 moles of H2. This can happen if the reaction is not complete or if there are other factors affecting the amount of gas produced. However, it is important to make sure that your experimental values are accurate and that all measurements were taken correctly.

In order to accurately determine the molar volume of H2 gas at STP, it would be helpful to repeat the experiment multiple times and take the average of the results. This can help account for any errors or inconsistencies in the data. Additionally, make sure to use the correct molar mass for H2 (2.016 g/mol) when calculating the moles of gas reacted.

I hope this helps and good luck with your experiment!
 

1. How do you calculate the molar volume of H2 gas at STP with Mg ribbon?

To calculate the molar volume of H2 gas at STP with Mg ribbon, you will need to use the ideal gas law equation, PV = nRT. First, measure the mass of the magnesium ribbon and record its value. Then, use the balanced chemical equation for the reaction between Mg and HCl to determine the moles of H2 gas produced. Next, measure the volume of the H2 gas produced using a gas collection method. Finally, plug in the values into the ideal gas law equation, making sure to convert to the appropriate units, to calculate the molar volume of H2 gas at STP.

2. What is the purpose of using Mg ribbon in the experiment?

Magnesium ribbon is used in the experiment as a source of H2 gas. When it reacts with HCl, it produces hydrogen gas, which can then be collected and used to calculate the molar volume of H2 gas at STP. Using a known mass of Mg ribbon also allows for the determination of the moles of H2 gas produced in the reaction.

3. How does STP affect the molar volume of H2 gas?

STP, or standard temperature and pressure, is defined as a temperature of 273 K (0°C) and a pressure of 1 atmosphere (atm). At these conditions, one mole of any ideal gas will occupy a volume of 22.4 liters. This means that the molar volume of H2 gas at STP will be 22.4 L/mol.

4. What are the limitations of using the ideal gas law to calculate molar volume?

The ideal gas law assumes that gases behave ideally, meaning that they have no volume, no intermolecular forces, and undergo perfectly elastic collisions. In reality, gases do have volume and interact with one another, especially at high pressures. These factors can cause deviations from the ideal behavior and affect the accuracy of calculations using the ideal gas law.

5. How can the experiment be improved to increase the accuracy of the molar volume calculation?

To improve the accuracy of the molar volume calculation, the experiment can be repeated multiple times and the average value can be taken. Using a larger mass of Mg ribbon can also improve the accuracy, as it will produce a larger volume of H2 gas. Additionally, ensuring that the equipment is properly calibrated and accurate measurements are taken can also increase the accuracy of the molar volume calculation.

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