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Homework Help: Chemical bonds

  1. Jan 31, 2005 #1
    What is the formula for copper (II) chlorate?

    a. CuClOsubscript 3
    b. Cu(ClOsubscript 3) subscript 2
    c. CuCl
    d. CuClsubscript 2

    Please help if you don't mind.
     
  2. jcsd
  3. Jan 31, 2005 #2

    dextercioby

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    I don't mind.What's your idea??

    Daniel.
     
  4. Jan 31, 2005 #3
    I believe it is A. I am pretty sure that B and C are wrong because of the oxidation numbers not equaling zero.

    Am I correct in my thinking?
     
  5. Jan 31, 2005 #4

    dextercioby

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    NO.
    What is the ON for each element...??What about the radical "chlorate"...??

    Daniel.
     
  6. Jan 31, 2005 #5
    What is C?
     
  7. Jan 31, 2005 #6

    dextercioby

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    What "C" are you talking about...??There's a [itex] Cl [/itex] which is the chemical symbol for Chlore...

    Answer the question regarding the ON-s...

    Daniel.
     
  8. Jan 31, 2005 #7
    Sorry, answer choice B.
     
  9. Jan 31, 2005 #8

    dextercioby

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    Don't HIT AND RUN...How did u figure it out...??What was your logics??

    Daniel.
     
  10. Jan 31, 2005 #9
    By the process of elimination.....

    Seriously, though, I don't understand this concept. Can you just explain it to me?

    Anyways, thank you for your time and effort if you are too busy.
     
  11. Jan 31, 2005 #10

    dextercioby

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    The chlorate radical [itex] ClO_{3} [/itex] has ON [itex] -1 [/itex] ,simply because the oxygen has ON [itex] -2 [/itex] (as in most of its compounds) and the chlore has ON [itex] +5 [/itex] (and you should figure out from the suffix "ate" and the lack of any prefix).
    On the other side,the copper atom has ON [itex] +2 [/itex] (because the problem says so,it may have ON [itex] +1 [/itex] as well).
    So to form a NEUTRAL MOLECULE,you need two radicals and one copper atom...

    Daniel.
     
  12. Jan 31, 2005 #11
    Thanks! I got it.
     
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