Chemical Equilibrium, finding concentration

  • Thread starter parwana
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  • #1
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H2(g) + I2(g) = 2HI(g)

T = 731K
K = 49.0


If at equilibrium 0.171 mol H2 and 1.571 mol I2 are present in a 1.04 L vessel, what is the concentration of HI in the gaseous mixture in moles/liter ?

Ok I tried doing this question by setting up a mole ratio first and then finding moles for HI, but I dont get it. HELP.
 

Answers and Replies

  • #2
187
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So we know that

[tex]K=\frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex]
that is
[tex]49=\frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex]

now for the concentrations of H2 and I2, we take the number of moles and divide by 1.04, the size of the container.

Then we can put these two numbers in for

and [I2] in the above equation and solve for the concentration of HI.

hope it helped

 
  • #3
GCT
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ChemRookie had a similar question in the high school HW section, of which I attempted an answer.
 

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