# Chemical Kinetics

2NO + 2H2 --> N2 + 2H2O

The concentration of NO is 0.006 M and the concentration for H2 is 0.002M. How can I find the concentration of NO remaining when one-half of the original amount of H2 has been consumed?

if you can also show me how it would be done if the reaction was not 1:1, that would help alot. thanks

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Borek
Mentor

It is a basic stoichiometry. To simplify things you can assume 1L volume. How many moles of H2 reacted if half was consumed? How many moles of NO reacted with this amount of hydrogen?

2NO + 2H2 --> N2 + 2H2O

The concentration of NO is 0.006 M and the concentration for H2 is 0.002M. How can I find the concentration of NO remaining when one-half of the original amount of H2 has been consumed?

if you can also show me how it would be done if the reaction was not 1:1, that would help alot. thanks

Here the molar ratio for NO and H2 is 1:1.

We know that 1/2 of original H2 remains
0.002/2 =0.001
for every 1 NO 1 H2 gets used up
for every 0.001 NO 0.001 H2 gets used up

0.006-0.001 =0.005 NO remaining

Borek
Mentor
Have you read the forum rules? Please don't do homework for others. A week passed, but it is not a reason to give final answers.