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I got a couple of questions regarding the following chemical reaction.

First some calculations:

[tex] 90,0 \textrm{mL of} \ 0,250 \ \textrm{M} \ BaCl_{2}[/tex] is mixed with [tex]0,500 \textrm{M}[/tex] of [tex] Na_{2} CO_{3} [/tex] which generats residuum.

a) [tex] BaCl_{2} \rightarrow Ba^{2+} + 2Cl_{2}^{-} \ (i) [/tex]

[tex] Na_{2} CO_{3} \rightarrow 2Na^{+} + CO_{3}^{2-} \ (ii) [/tex]

b) The mol mass of (i) and (ii) are:

[tex]C(BaCl_{2}) = \frac{n(BaCl{2})}{V(BaCl{2})} \rightarrow n(BaCl_{2}) = C(BaCl_{2})} \cdot V(BaCl_{2}) = 0,09 L \cdot 0,25 L/mol = 0,0,225 \textrm{mol}[/tex]

[tex]C(Na_{2}CO_{3}) = \frac{n(Na_{2}CO_{3})}{V(Na_{2}CO_{3}} \rightarrow n(Na_{2}CO_{3}) = C(Na_{2}CO_{3}) \cdot V(Na_{2}CO_{3}) = 0,08 L \cdot 0,50 L/mol = 0,040 \textrm{mol}[/tex]

c) The Chemical reaktion schema for the mixture of [tex] BaCl_{2} [/tex] and [tex] Na_{2} CO_{3} [/tex] is:

[tex] Ba Cl_{2} + Na_{2} CO_{3} \rightarrow BaCO_{3} + 2NaCl [/tex]

I got two questions:

1) I would like to calculate the residuum generated in [tex] Ba Cl_{2} + Na_{2} CO_{3} \rightarrow BaCO_{3} + 2NaCl \ ??? [/tex]

2) Second I would like to Calculate [tex][Na^{+}][/tex] in c) ??

Many thanks in advance !

Sincerely

Fred

Denmark