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Chemical Reaction, need help!

  1. Mar 1, 2005 #1
    Hey guys could you tell me if I got the right answer; my teacher hasn't went over this material and it is due tomorrow.

    Given the following reaction, how many grams of Zn are required to obtain 2.00g of Au?
    [tex]4CN^{-1}~+~3Zn~+~2Au(CN)_4^{-1}~~-->~3Zn(CN)_4^{-2}~+~2Au[/tex]

    (2.00g of Au)(1 mole Au/179.0g of Au)(3 mole Zn/2 mole Au)(65.39g Zn/1 mole Zn) = 1.10g of Zn

    Is this the proper way and is my answer correct? Thanks
     
  2. jcsd
  3. Mar 1, 2005 #2
    taht is the correct way of doing it, just be careful of ratios always
     
  4. Mar 2, 2005 #3

    dextercioby

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    And one more thing.Use the same # of significant digits when working with molar masses.

    Daniel.
     
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