1. The problem statement, all variables and given/known data Explain why copper(II) is the more common oxidation state than copper (I) by giving the electronic configurations of the ions involved. 3. The attempt at a solution i've considered about the configurations of Cu+ and Cu2+ but the result seems to contradict the fact. Cu+:[Ar]3d^10 Cu2+:[ar]3d^9 Base on the configuration, Cu2+ should be readily reduced to Cu+,so Cu+ should be the more common oxidation state in this regard. Please help correct mistakes i've make, or did i think in a wrong way? thanks.