• Support PF! Buy your school textbooks, materials and every day products Here!

Chemistry Electronic Configuration

  • Thread starter chriswwt
  • Start date
5
0
1. Homework Statement
Explain why copper(II) is the more common oxidation state than copper (I) by giving the electronic configurations of the ions involved.


3. The Attempt at a Solution
i've considered about the configurations of Cu+ and Cu2+ but the result seems to contradict the fact.
Cu+:[Ar]3d^10
Cu2+:[ar]3d^9
Base on the configuration, Cu2+ should be readily reduced to Cu+,so Cu+ should be the more common oxidation state in this regard.
Please help correct mistakes i've make, or did i think in a wrong way?
thanks.
 
5
0
so now the new configuration is
Cu+:3d^8 4s^2
Cu2+:3d^7 4s^2
cu2+ has 3 unpaired 3d electrons whereas Cu+ has 2 unpaired electrons, in theory the unpaired electrons in Cu2+ will repelled from the inner electrons and thus more unstable?
 
5
0
well i find that the original configuration i proposed should be correct since the atom tends to retain the extra stability of fully filled 3d subshell.....
 

Related Threads for: Chemistry Electronic Configuration

Replies
0
Views
3K
Replies
1
Views
1K
Replies
8
Views
51K
  • Last Post
Replies
1
Views
52K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
9
Views
2K
  • Last Post
Replies
8
Views
6K
Top