- #1
erik05
- 50
- 0
Hello all, this question is really simple but I still seem to get it.
A 50.0 mL sample of 0.500 mol/L [tex] MgSO_4 [/tex] solution at 24.4 degrees celsius is added to 50.0 mL of a 0.500 mol/L [tex] Ba(NO_3)_2 [/tex] solution at 24.4 degrees celsius. The temperature of the mixture rises to 26.3 degrees celsius. Calculate the heat of reaction.
I tried using [tex] mc\triangle{t} + mc\triangle{t} [/tex] but there is no specific heat capacity for either of the compounds. I'm guessing the formula [tex] \triangle{H}=nH [/tex] fits in somewhere but I don't know where. Any hints or suggestions would be appreciated. Thanks.
A 50.0 mL sample of 0.500 mol/L [tex] MgSO_4 [/tex] solution at 24.4 degrees celsius is added to 50.0 mL of a 0.500 mol/L [tex] Ba(NO_3)_2 [/tex] solution at 24.4 degrees celsius. The temperature of the mixture rises to 26.3 degrees celsius. Calculate the heat of reaction.
I tried using [tex] mc\triangle{t} + mc\triangle{t} [/tex] but there is no specific heat capacity for either of the compounds. I'm guessing the formula [tex] \triangle{H}=nH [/tex] fits in somewhere but I don't know where. Any hints or suggestions would be appreciated. Thanks.