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Chemistry - equation problem

  1. Sep 18, 2007 #1


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    1. The problem statement, all variables and given/known data

    1) ok , first we have a solution of :
    MnO2, C6H5COO- , OH-

    we add Hydrochloric acid, the following reactions happen :
    OH- + H3O+ = H2O
    C6H5COO- + H3O+ = C6H5COOH + H2O

    ok , now we are told that if we put in more Hydrochloric acid than needed, CO2 gas escapes, a question asks me for the equations of the reactions that produce this CO2

    I am just told these Acid/Base couples :
    HCO3- / CO3-2
    CO2, H2O / HCO3-

    2) No, with the same solution, with Hydrochloric acid being introduced in about the right proportions, we add a solution of (2Na+ +SO3-2)
    Here, another question asks me for the equation of the reaction between MnO2 and SO2,H20

    Here i am just told these Red/Ox couples :
    MnO2 / Mn+2
    SO3-2 / SO2, H2O

    The Reaction environment is acid

    2. Relevant equations

    3. The attempt at a solution

    the semi equations :
    HCO3- = CO3-2 + H+
    CO2 + H2O = HCO3- + H+

    C6H5COOH + H3O(+) = C6H5 + CO3-2 + 3H+ + H (cannot be H alone so * 2) :
    2C6H5COOH + 2H3O(+) = 2C6H5 + 2CO3-2 + 6H+ + H2

    CO3-2 + H+ = HCO3-
    HCO3- + H+ = H2O + CO2

    (here, im really not sure of my equations,and the paper doesnt even tell me that H2 gas escapes)

    2) The semi equations :

    MnO2 + 4H+ 2e- = Mn+2 + 2H2O

    SO3-2 + 2H+ = SO2 + H2O (no e- in the reactions !!, how can it be an Ox/red reaction then ?)
    Last edited: Sep 18, 2007
  2. jcsd
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