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Chemistry Help

  1. Apr 3, 2004 #1
    Chemistry Help-Enthalpy

    Hi. I would very much like to know how to calculate the enthalpy change of a neutralization reaction, for example, NaOH(aq) and HCl(aq).
    Thank you very much.
     
    Last edited: Apr 3, 2004
  2. jcsd
  3. Apr 4, 2004 #2
    Strong acid + strong base has an enthalpy of neutrailzation = -13.7 Kcal

    which is the case here
     
  4. Apr 4, 2004 #3

    ShawnD

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    I get a different answer based on some data tables I have.
    http://myfiles.dyndns.org/datasheets/chem_enthalpy1.jpg [Broken]
    http://myfiles.dyndns.org/datasheets/chem_enthalpy2.jpg [Broken]

    Energies are in KJ

    delta H = [water + sodium chloride] - [hydrogen chloride + sodium hydroxide]
    delta H = [-285.8 - 411.2] - [-92.3 - 425.6]
    delta H = -179.1 KJ / mol

    Thats about -43 Kcal / mol
     
    Last edited by a moderator: Apr 20, 2017 at 7:49 PM
  5. Apr 4, 2004 #4

    GCT

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