(adsbygoogle = window.adsbygoogle || []).push({}); 1. A certain reaction has an activation energy of 54.0 kJ/mol. As the temperature is increased from 22degrees celsius to a higher temperature, the rate constant increases by a factor of 7.00. Calculate the higher temperature.

2. ln(k)=-Ea/RT + ln(A)

3. i dont think that i have enough information because when i plugged the values given and there are still two variables. Then i tried simultanious equations by solving for [A] and there are still two variables the new temp and the rate constant. So if anyone can help it would be very appreciated.

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# Chemistry kenitics problem

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