1. The problem statement, all variables and given/known data A plant takes in 20.24 kg/day Al, 24.04 kg/day S8, 48.00 kg/day 02, and 753 kg/day H2O. It's product stream is 254.3 kg/day AlSO4+12(H2O). The rest of it's water goes to "other things". How much water goes to other things? 2. Relevant equations 20.24+24.04+48.00+753=845.28 kg - 254.3 = 590.98 kg = 591 L/d 3. The attempt at a solution I added the masses of the raw materials, subtracted the mass of the product stream, and the remainder is the water used for "other things." It seems easy enough to me, but the simplicity of the question is giving me pause, as it's the first question in this course which seemed this simple. My result was 591 L/d. Basically I want to know if I did this correctly, or am I barking up the completely wrong tree. If I'm wrong, I'd appreciate it if someone told me, but left it at that, as I'd like to try and figure it out on my own. Thanks in advance.