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Homework Help: Chemistry Lab

  1. May 10, 2007 #1
    A quick question that would request a quick response.. please help.

    Prepare, by mixing proper quantities of silver nitrate and sodium acetate solutions, approximately 0.3 millimole of silver acetate. Wash this precipitate with a small quantity of distilled water and transfer it to a test tube containing 10 mL of distilled water. Warm the test tube and its contents for 15 minutes, using a water bath held at 40 degrees C (+/-) 5 degrees C, stirring intermittently. Cool the contents to 0 degrees C. Then filter. Divide the filtrate into two approximately equal portions. To one portion add 0.5 mL of 3 M sodium acetate solution; to the other add 0.5 mL of 3 M acetic acid solution. Wait. Why did a precipitate form in one case and not in the other?

    Thanks a bunch
  2. jcsd
  3. May 11, 2007 #2


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    common ion effect.
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