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Chemistry: pH after adding water

  1. Mar 12, 2005 #1
    I am trying to find what the new concentration of [tex]OH^{-}[/tex] in a solution of potassium hydroxide (pH = 11.65) is after diluting it with water to six times the original volume. It is at 298.15 K (25 degrees Celcius).

    I have found the concentration of [tex]H_{3}O^{+}[/tex] and I guessed that I just multiply the volume times six (divide the concentration by six) to find the new concentration, would this be a correct way to approach this problem?
  2. jcsd
  3. Mar 13, 2005 #2

    where c is concentration and v is volume. Find the initial [OH-], then use the above formula and the information given to find the new concentration.
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