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Mg + H2SO4 ----> MgSO4 + H2

Cacluate the minimum mass of magnesium metal that would be required to completely neutralise 0.50 L of 1.0 mol l-1 sulfuric acid.

My calculations so far ...

Mr(H2SO4) = 2xAr(H) + Ar(S) + 4xAr(O)

= 98

Mr(MG) = 24.31

Molarity = 1.0mol / 0.50L = 2

But I am at a loss as to how I get to the final answer .....

Any help would be most appreciated !