A diving bell has an air space of 3.0 m2 when on the deck of a boat. What is the volume of the air space when the bell has been lowered to a depth of 50 m? Take the mean density of sea water to be 1.025 g cm-3 and assume that the temperature is the same as on the surface.
PV = nRT
The Attempt at a Solution
I'm thinking I should use the ideal gas law to solve this problem.
V1P1 = nRT
V2P2 = nRT
V1P1 = V2P2
P1 = 1 atm (at surface of water)
P2 = ? (would I use the density of sea water and surface area of diving bell somehow?)