Chemistry question

  • Thread starter winterwind
  • Start date
  • #1
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Homework Statement


A diving bell has an air space of 3.0 m2 when on the deck of a boat. What is the volume of the air space when the bell has been lowered to a depth of 50 m? Take the mean density of sea water to be 1.025 g cm-3 and assume that the temperature is the same as on the surface.


Homework Equations



PV = nRT

The Attempt at a Solution



I'm thinking I should use the ideal gas law to solve this problem.

V1P1 = nRT

V2P2 = nRT

V1P1 = V2P2

P1 = 1 atm (at surface of water)

P2 = ? (would I use the density of sea water and surface area of diving bell somehow?)

Thanks!
 

Answers and Replies

  • #2
277
1
[tex]P_{2}=P_{1}+\rho g \Delta z[/tex]
where
g=gravitational acceleration
[tex]\Delta z[/tex]= difference in depth
 

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