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Chemistry question

  1. Sep 13, 2009 #1
    1. The problem statement, all variables and given/known data
    A diving bell has an air space of 3.0 m2 when on the deck of a boat. What is the volume of the air space when the bell has been lowered to a depth of 50 m? Take the mean density of sea water to be 1.025 g cm-3 and assume that the temperature is the same as on the surface.


    2. Relevant equations

    PV = nRT

    3. The attempt at a solution

    I'm thinking I should use the ideal gas law to solve this problem.

    V1P1 = nRT

    V2P2 = nRT

    V1P1 = V2P2

    P1 = 1 atm (at surface of water)

    P2 = ? (would I use the density of sea water and surface area of diving bell somehow?)

    Thanks!
     
  2. jcsd
  3. Sep 13, 2009 #2
    [tex]P_{2}=P_{1}+\rho g \Delta z[/tex]
    where
    g=gravitational acceleration
    [tex]\Delta z[/tex]= difference in depth
     
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