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## Homework Statement

What is the solubility (M) of PbCl2 in a0.15M solution of HCl? The Ksp of PbCl2 is 1.6*10^-5

answer is 7.4*10^-4

## Homework Equations

Ksp= [Pb] * [Cl]^2

## The Attempt at a Solution

Like the other question I posted I need help with the working. I tried 4x^3 = 1.6*10^-5 which led to wrong answer and also 1.6*10^-5 / different forms of 0.15 [(0.15), (0.15*2), (0.15^2), (2*0.15^2)]