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Chemistry - vapor pressure

  1. Oct 20, 2008 #1
    1. The problem statement, all variables and given/known data
    What is the capor pressure of a solution containing .15 mol of glucose (C6H12O6) and 1.65 mol of water at a temperature of 60.0C? the vapor pressure of pure water at this temperature is 149.38 torr


    2. Relevant equations
    Ralout's law?

    P=PoX


    3. The attempt at a solution
    im guessing that the P on the left side of the eqn is is VP of pure water(149.38)

    im not sure how to get x there is some formula like nsolute/(nsolute + nsolvent)


    thanks
     
  2. jcsd
  3. Oct 20, 2008 #2

    Borek

    User Avatar

    Staff: Mentor

    You are on the right track.
     
  4. Oct 20, 2008 #3
    how do i find X
     
  5. Oct 20, 2008 #4

    Borek

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    Staff: Mentor

    Using formula like the one you have listed, just remember you are looking for molar fraction of solvent, not solute.
     
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