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Chern-Simons action

  1. Oct 26, 2014 #1
    I have the Chern Simons action, and I've found the equations of motion ##\epsilon^{\mu\nu\rho}F_{\nu\rho}=0##. A problem I was looking at said show that the e.o.m. is "gauge equivalent to the trivial solution". I understand what this means. Obviously the e.o.m. is manifestly gauge invariant, and this is trivial to show, so I don't know what else to do.
     
  2. jcsd
  3. Oct 31, 2014 #2
    Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
     
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