I have the Chern Simons action, and I've found the equations of motion ##\epsilon^{\mu\nu\rho}F_{\nu\rho}=0##. A problem I was looking at said show that the e.o.m. is "gauge equivalent to the trivial solution". I understand what this means. Obviously the e.o.m. is manifestly gauge invariant, and this is trivial to show, so I don't know what else to do.(adsbygoogle = window.adsbygoogle || []).push({});

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# Chern-Simons action

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