(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In a cross between two types of pea plants, one heterozygous for the round yellow seed condition, and the other, pure breeding with wrinkled green seeds, the following offsprings were recorded;

Round yellow peas-- 108

Round green peas-- 102

Wrinkled yellow peas--105

Wrinkled green peas-- 101

2. Relevant equations

[tex]\chi[/tex] ^2 = [tex]\Sigma[/tex] {O-E)^2 / E}

The ratio of a heterozygous cross with a homozygous recessive

3. The attempt at a solution

I calculated the value of [tex]\chi[/tex] ^2 to be 0.28. The degrees of freedom= no. of categories-1 = 3.

I'm a little bit confused on how to relate the calculated value of [tex]\chi[/tex] ^2 to the probability value in the distribution table.

I took the probability value as > 0.1 and got 6.25 according to the data in the table. I'm now assuming that it isn't a significant deviation as the value of [tex]\chi[/tex] ^2 is much smaller than this (0.28).

Can someone please explain this if I'm on the wrong track. Thanks

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# Homework Help: Chi- squared test

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